What is the value of Kp at 1000C for the followingreaction? CaCO3(s) <--> CaO(s)
ID: 683836 • Letter: W
Question
What is the value of Kp at 1000C for the followingreaction?CaCO3(s) <--> CaO(s) + CO2(g) H f (kJ/mol) -1206.9 -635.1 -393.5 S (J/K) 92.9 38.2 213.7 Gf (kJ/mol) -1128.8 -603.5 -394.4 please show detailed steps so that I may understand how tocomplete this problem. Thank you very much! What is the value of Kp at 1000C for the followingreaction?
CaCO3(s) <--> CaO(s) + CO2(g) H f (kJ/mol) -1206.9 -635.1 -393.5 S (J/K) 92.9 38.2 213.7 Gf (kJ/mol) -1128.8 -603.5 -394.4 please show detailed steps so that I may understand how tocomplete this problem. Thank you very much! CaCO3(s) <--> CaO(s) + CO2(g) H f (kJ/mol) -1206.9 -635.1 -393.5 S (J/K) 92.9 38.2 213.7 Gf (kJ/mol) -1128.8 -603.5 -394.4
Explanation / Answer
We Know that : The given Reaction is : CaCO3 <--------> CaO + CO2 H = H ( products ) - H ( reactants ) = [-635.1 + ( -393.5 ) ] KJ - [ -1206.9 ] KJ = 178.3 KJ S = S ( products ) - S ( reactants ) = [ 213.7 + 38.2 ] J / K - [ 92.9 ] J/K = 159 J / K G = H - T S = 178x 103 J - 298 K x 159 J / K = 130618 J G0 = G products - Greactants = -394 + (-603.5) - [ -1128.8 ] = 131.3 KJ G = G0 + RTlnK 131300 J - 130618J = 8.314 J / mol-K x 298K lnK K = 1.3168 H = H ( products ) - H ( reactants ) = [-635.1 + ( -393.5 ) ] KJ - [ -1206.9 ] KJ = 178.3 KJ S = S ( products ) - S ( reactants ) = [ 213.7 + 38.2 ] J / K - [ 92.9 ] J/K = 159 J / K G = H - T S = 178x 103 J - 298 K x 159 J / K = 130618 J G0 = G products - Greactants = -394 + (-603.5) - [ -1128.8 ] = 131.3 KJ G = G0 + RTlnK 131300 J - 130618J = 8.314 J / mol-K x 298K lnK K = 1.3168Related Questions
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