What is the total pressure, in atm, of a2.00 Litre vessel containing 2.0 greams

Question

What is the total pressure, in atm, of a2.00 Litre vessel containing 2.0 greams of Hydrogen and 1.0 gram ofHelium at 25 Celcius. I basically just used the PV=nRT formula. This is how i set itup: (P)(2.00)=n(.082057)(25+273.15). I want to find "n" (moles) in order to find thepressure.... but i don't know where to go from there. I would verymuch appreciate any help. Please and Thankyou. -Sandy What is the total pressure, in atm, of a2.00 Litre vessel containing 2.0 greams of Hydrogen and 1.0 gram ofHelium at 25 Celcius. I basically just used the PV=nRT formula. This is how i set itup: (P)(2.00)=n(.082057)(25+273.15). I want to find "n" (moles) in order to find thepressure.... but i don't know where to go from there. I would verymuch appreciate any help. Please and Thankyou. -Sandy

Explanation / Answer

                      Number of moles of hydrogen = 2.0 g / 2.016g/mol                                                           = 0.992 mol            Number of moles of helium = 1.0 g / 4.003g/mol                                                       = 0.2498 mol           totalnumber of moles = n = 1.2418 mol            P * 2.0 L   = 1.2418 mol * 0.0821 L.atm/mol.K *298 K             P = 15.19 atm

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