1) what volume will 500ml of gas @ 20oc and a pressureof 420 mmhg occupy if the
ID: 684261 • Letter: 1
Question
1) what volume will 500ml of gas @ 20oc and a pressureof 420 mmhg occupy if the temperature is reduced to 80oc and thepressure to 650 mmhg 2)A sample of gas of mass 2.82 g occupies a volume of639 ml @ 27oC & 1.00atm pressure.what is the molar mass of thegas 3) a gas is placed in a storage tank @ a pressure of 30.0 atm@ 20.3oc as a safety device there is a small metal plug in the tankof a metal alloy that melts @ 130oC. if the tank is heated what isthe maximum presure that will be attained in the tank before theplug will melt and release gas. 4)forty liters of a gas were collected over water when thebarometer read 6222.0mmhg, and the temperature was 20oC WHAT VOLUMEWOULD THE DRY GAS OCCUPY @ STANDARD CONDITIONS 5)Five moles of hydrogen gas @ OoC are forced into a steelcylinder with aa volume of 2.0L WHAT is the pressure of thegas in the cylinder. 1) what volume will 500ml of gas @ 20oc and a pressureof 420 mmhg occupy if the temperature is reduced to 80oc and thepressure to 650 mmhg 2)A sample of gas of mass 2.82 g occupies a volume of639 ml @ 27oC & 1.00atm pressure.what is the molar mass of thegas 3) a gas is placed in a storage tank @ a pressure of 30.0 atm@ 20.3oc as a safety device there is a small metal plug in the tankof a metal alloy that melts @ 130oC. if the tank is heated what isthe maximum presure that will be attained in the tank before theplug will melt and release gas. 4)forty liters of a gas were collected over water when thebarometer read 6222.0mmhg, and the temperature was 20oC WHAT VOLUMEWOULD THE DRY GAS OCCUPY @ STANDARD CONDITIONS 5)Five moles of hydrogen gas @ OoC are forced into a steelcylinder with aa volume of 2.0L WHAT is the pressure of thegas in the cylinder.Explanation / Answer
a) PV=nRT (420/760 atm)(.500 L) = n(.0821)(20+273 K) n = .0115 mol PV= nRT (650/760 atm)(V) = .0115 x .0821 x (80+273 K) V = .389 L or 389 mL b) PV = nRT (1.00 atm)(.639 L) = n(.0821)(27+273) n = .0259 mol n = mol = g/Molar mass .0259 = 2.82 g / X X = molar mass = 108.7 g/mol
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