Find H in Joules for: Mg 2 SiO 4 +SiO 2 --> 2MgSiO 3 with the followingdata: Mg

Question

Find H in Joules for: Mg2SiO4 +SiO2 --> 2MgSiO3 with the followingdata: Mg + 3/2 O2 + Si -->MgSiO3                     H = -1497.4 kJ/mol Si + O2 -->SiO2                                           H= -859.4 kJ/mol 2Mg + 2O2 + Si -->Mg2SiO4                      H= -2042.6 Kj/mol Thank you all. Find H in Joules for: Mg2SiO4 +SiO2 --> 2MgSiO3 with the followingdata: Mg + 3/2 O2 + Si -->MgSiO3                     H = -1497.4 kJ/mol Si + O2 -->SiO2                                           H= -859.4 kJ/mol 2Mg + 2O2 + Si -->Mg2SiO4                      H= -2042.6 Kj/mol Thank you all.

Explanation / Answer

Mg + 3/2 O2 + Si -->MgSiO3                     H 1 = -1497.4kJ/mol            -------------- ( 1 ) Si + O2 -->SiO2                                           H2 = -859.4kJ/mol             --------------- ( 2 ) 2Mg + 2O2 + Si -->Mg2SiO4                      H3 = -2042.6Kj/mol            ---------------- ( 3 )
Mg2SiO4 + SiO2 -->2MgSiO3 can be obtained by 2 * Eq ( 1 ) +reverse of Eq ( 2 ) + reverse of Eq ( 3 ) So, H of the above Equation is H = 2*  H 1 + ( -  H2 ) + ( -  H 3 )                                                        = 2 * ( -1497.4 ) + 859.4 + 2042.6                                                        = - 92.8 KJ / mol                                                        = -92.8 * 1000 J / mol                                                        = 92800 J / mol

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