the equilibrium constant kp for the reaction is found to be0.000431at 200degree

Question

the equilibrium constant kp for the reaction is found to be0.000431at 200degree c N2 gaz +3H2gaz----------------2NH3 gaz in a certain experiment a student starts with 0.666atmof N2 and 0.333 atm of H2 FIND THE partial pressure when allspecies reach equlibrium in the flask the equilibrium constant kp for the reaction is found to be0.000431at 200degree c N2 gaz +3H2gaz----------------2NH3 gaz in a certain experiment a student starts with 0.666atmof N2 and 0.333 atm of H2 FIND THE partial pressure when allspecies reach equlibrium in the flask

Explanation / Answer

              N2 (g) +      3H2        =>   2NH3 initial       0.666        0.333                    0 change   0.666-x     0.333-3x               +2x K = [NH3]2/{[H2]3*[N2]} = (2x)2/{(0.333 -3x)3*(0.666-x)}= 0.000431 Let 0.333 - 3x ~ 0.333 and 0.666 - x ~ 0.666 Solve (2x)2/{ (0.333)3*(0.666)}= 0.000431 x = 1.63 x 10-3    (note that because xis so small, approximating 0.333 - 3x ~ 0.333 is justifiable) PN2 = 0.666 -x = 0.664 atm PH2 = 0.333 - 3*x = 0.328 atm PNH3 = 2*x = 3.26 x 10-3 atm

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