I am getting a little stuck on this problem: The following data were obtained fr

Question

I am getting a little stuck on this problem: The following data were obtained from experiments to fins themolecular formula of bezocaine, a local anesthetic, which containsonly carbon, hydrogen, nitrogen, and oxygen. Complete combustion ofa 3.54 g sample of benzocaine with excess O2 formed 8.49 g of CO2 and 2.14 g H2O. Anothersample of mass 2.35 g was found to contain .199 g N. The molar massof benzocaine was gound to be 165. Find the molar formula. So I calculated the moles of C to be .19295 moles and the moles of H to be .237777 moles. I don't know what todo from here in order to get the moles of Oxygen and Nitrogen sincethere are multiple samples and you don't have all the informationfor all the elements for each sample. I know you can calculate themoles of benzacain (.021454 moles) but I am not sure what to dowith that. Thanks! :) I am getting a little stuck on this problem: The following data were obtained from experiments to fins themolecular formula of bezocaine, a local anesthetic, which containsonly carbon, hydrogen, nitrogen, and oxygen. Complete combustion ofa 3.54 g sample of benzocaine with excess O2 formed 8.49 g of CO2 and 2.14 g H2O. Anothersample of mass 2.35 g was found to contain .199 g N. The molar massof benzocaine was gound to be 165. Find the molar formula. So I calculated the moles of C to be .19295 moles and the moles of H to be .237777 moles. I don't know what todo from here in order to get the moles of Oxygen and Nitrogen sincethere are multiple samples and you don't have all the informationfor all the elements for each sample. I know you can calculate themoles of benzacain (.021454 moles) but I am not sure what to dowith that. Thanks! :)

Explanation / Answer

do you mean 1.99 g of N? or is it really 0.199 g N?

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