Hello, would anyone mind helping me? I\'d greatly appreciateit!! Will rate lifes

Question

Hello, would anyone mind helping me? I'd greatly appreciateit!! Will rate lifesaver for the correct answer :)

Benzoic Acid FM: 122.12 g/mol
Naphthalene FM: 128.17 g/mol

You have a mixture that contains 125mg of benzoic acid and 100mg ofnaphthalene. What volume in mL of 3.5 M NaOH must you add toconvert all of the benzoic acid to sodium benzoate without anyexcess NaOH remaining?

Explanation / Answer

First balance the equation C6H5CO2H (aq) + OH- (aq) -->C6H5CO2- (aq) +H2O (l) It is a 1:1 stoichiometric ratio. First you must calculate the moles of NaOH necessary using thestoichiometric ratio. You can use the molarity of the NaOH soln tothen calculate the volume. (125 mg benzoic acid)(1 g benzoicacid / 1000 mg benzoicacid)(1 mol benzoic acid / 122.12g benzoic acid)(1 mol NaOH / 1mol benzoic acid)(1 L of soln /3.5 moles NaOH)(1000 mL soln / 1L soln) = 0.30 mL3.5M NaOH soln (I'm not sure if this is entirely correct since I'm not sure whyNaphthalene is included in the question?)

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