hi all, i am having problem with calculating ionization energy how do you get th

Question

hi all, i am having problem with calculating ionization energy
how do you get the IE1, IE2, IE3 of an element
the textbook has this formula
X(g) ----------> X+(g)+e-  
E=IE1
i need to make a logarithm for Be of the ionization energy versusthe number of electrons removed from Be.
But i can't seem to get the right number
i have like a table for the ionization energy
but the book shows an example of Na
which Na has IE1=0.50 IE2=4.56
but on the book's logarithm graph, helium has IE1 below 0.00
and IE2 below 1.00
the graph's y axis says logIn(MJ mol-1)
the x axis is n

Explanation / Answer

see, for BE, the 1st ionization energy = 899.5 kJ mol-1 =0.8995 MJ mol-1 2nd ionization energy = 1757.1 kJ mol-1 =1.7571 MJ mol-1 so log ( 0.8995 ) is certainly negative. also log ( 0.8995 ) = positive and less than 1.00 NOTE : do remember to convert energy in Mega joules = 10 ^ 6Joules             also log (x) > 0 if x >1                    log (x)

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.