How will you prepare the following solutions from 6.0 M solutions of acetic acid

Question

How will you prepare the following solutions from 6.0M solutions of acetic acid and ammonia? Give exactdetails. Assume that a 10-ml graduated cylinder (in which volumescan be read to the nearest 0.1 ml) and a 100-ml graduated cylinderare available. a. 80 ml of 0.10 MHC2H3O2 b. 80 ml of 0.10 M NH3 How will you prepare the following solutions from 6.0M solutions of acetic acid and ammonia? Give exactdetails. Assume that a 10-ml graduated cylinder (in which volumescan be read to the nearest 0.1 ml) and a 100-ml graduated cylinderare available. a. 80 ml of 0.10 MHC2H3O2 b. 80 ml of 0.10 M NH3 b. 80 ml of 0.10 M NH3

Explanation / Answer

Use the following equation: M1V1 = M2V2 M1V1 is the starting molarity and volume ofthe solution, and M2V2 is the resultantmolarity and volume after dilution of the original stocksolution. a) M1 = 6.0 MCH3CHO2H V1 = ? M2 = 0.10 M CH3CO2H V2 = 80 mL Solve for V1: V1 = (M2V2)/M2 = (0.10M)(80 mL)/(6.0M) = 0.1333 mL of 6.0M aceticacid Approximately ˜0.1mL of6.0M acetic acid solution must be placed into a 100mLgraduated cylinder, and then diluted with water to the 80mL mark.This will yield a ˜0.10M acetic acidsolution. The same will be done with the ammonia solution.

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