The valve between a 5-L tank containing a gas at 9 atm and a10-L tank containing

Question

The valve between a 5-L tank containing a gas at 9 atm and a10-L tank containing a gas a 6 atm is opened. Calculate the finalpressure in the tanks. please give the formula to use, what each number is inregards to the formula, and how to solve it. thanks The valve between a 5-L tank containing a gas at 9 atm and a10-L tank containing a gas a 6 atm is opened. Calculate the finalpressure in the tanks. please give the formula to use, what each number is inregards to the formula, and how to solve it. thanks

Explanation / Answer

The formula here is simple: P1V1 + P2V2 =P3V3 Where P is the pressure in atm Where V is the volume in L Where the subscript 1 refers to the first container, 2 refers tothe second container and 3 refers to the 'third' container which is a combinations ofboth of them when the valve is opened Rearranging we get P3 = (P1V1 +P2V2) / V3      = (9*5 + 6*10) / (5 + 10)      = 7 atm So the final pressure is 7 atm

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