This is a practice problem that my teacher wrote and assigned.Do I find the mola

Question

This is a practice problem that my teacher wrote and assigned.Do I find the molar solubility similar to finding the pH with theKa value? And is the second part of the question because there aremore calciun ions in than floride? Calcium fluoride Ca F 2 is an insolublesalt. The Ksp is 3.4 x 10 -11. Calculate the molarsolubility of calcium fluoride. If the concentration of fluoride influoridated drinking water is 1 x 10 -5 M and thecalcium ion concentration in blood is 2.5 x 10 -3 M ,why is there no danger of Ca F 2 precipitating in the blood stream,after drinking the water? This is a practice problem that my teacher wrote and assigned.Do I find the molar solubility similar to finding the pH with theKa value? And is the second part of the question because there aremore calciun ions in than floride? Calcium fluoride Ca F 2 is an insolublesalt. The Ksp is 3.4 x 10 -11. Calculate the molarsolubility of calcium fluoride. If the concentration of fluoride influoridated drinking water is 1 x 10 -5 M and thecalcium ion concentration in blood is 2.5 x 10 -3 M ,why is there no danger of Ca F 2 precipitating in the blood stream,after drinking the water?

Explanation / Answer

         CaF2  =>    Ca2+    +   2F-                               +x              +2x Ksp = [Ca2+][F-]2 = (x)(2x)2 = 4x^3 =3.4e-11 x = (3.4e-11/4)^(1/3) = 2.04 x10-4M        (solubility) ============ Q = [Ca2+][F-]2 = (2.5e-3)*(1e-5)^2 = 2.5e-13 Q

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