This is a multistep problem: Barium Carbonate with Ksp= 8.1E-9 I got the answers

Question

This is a multistep problem:

Barium Carbonate with Ksp= 8.1E-9

I got the answers for some but stuck on the last few:

C) I calculated the molar solubilitiy of barium carbonate in water at 25C?

answer: 9.0E-5M

D) Convert answer in part C to g/L

answer: 1.78E-2g/L

Here's where I got stuck at:

E) Suppose the molar concentration of Ba2+ and CO2-3 is 2.55E-9M. Classify this solution as Unsaturated, Saturated, or Supersaturated.

F) If HCl(aq) was titrated into a solution of Barium Carbonate, what reaction would occur?

G) As a result of the above titration, which direction would the dissolution reaction shift (according to Le Chatelier's Principle)?

Explanation / Answer

C) I calculated the molar solubilitiy of barium carbonate in water at 25C?

answer: 9.0E-5M Correct

D) Convert answer in part C to g/L

answer: 1.78E-2g/L   correct

E) Suppose the molar concentration of Ba2+ and CO2-3 is 2.55E-9M. Classify this solution as Unsaturated, Saturated, or Supersaturated.

Answer:-

Since the concentrations of the ions are given then lets calculate the Qsp and compare it with Ksp

Qsp = [Ba2+][ CO2-3 ]

Let put the concentration values in the formula

Qsp = [2.55E-9][ 2.55E-9]

Qsp = 6.5E-18

Qsp is very small than Ksp

Qsp << Ksp

Therefore solution is unsaturated.

F) If HCl(aq) was titrated into a solution of Barium Carbonate, what reaction would occur?

Answer :- HCl is the acid it will react with carbonate ion to form the carbonic acid which dissociate into the water and carbon dioxide gas following is the complete reaction equation

BaCO3(s) + 2HCl (aq)   -----> BaCl2(aq) + CO2(g) + H2O(l)

G) As a result of the above titration, which direction would the dissolution reaction shift (according to Le Chatelier's Principle)?

Answer :- According to the Le Chatelier's Principle the the reaction would shift to the right side direction means more BaCO3 will dissolve because it forms BaCl2 which is soluble in water. So adition of the HCl will cause CaCO3 to dissolve more and hence shifting reaction to right side. (more products forming)

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