acetanilide has the solubilities in water shown on thetable. temp(celsius) 100 d
ID: 687501 • Letter: A
Question
acetanilide has the solubilities in water shown on thetable. temp(celsius) 100 degrees(bp) 22degrees(rt) 0 degrees solubility(g/100ml) 5.10 0.52 0.10 a. How much acetanilide would be soluble in 200 ml ofwater at the boiling point? b. If this solution were cooled to room temp and filtered, howmany grams of acetanilide would be obtained? c. If the filtrate were concentrated to 50 ml and cooled to 0degrees, how many grams would be obtained in a second crop? My answers: a. 10.2 b. 1.04 c. 1.04 am i correct? acetanilide has the solubilities in water shown on thetable. temp(celsius) 100 degrees(bp) 22degrees(rt) 0 degrees solubility(g/100ml) 5.10 0.52 0.10 a. How much acetanilide would be soluble in 200 ml ofwater at the boiling point? b. If this solution were cooled to room temp and filtered, howmany grams of acetanilide would be obtained? c. If the filtrate were concentrated to 50 ml and cooled to 0degrees, how many grams would be obtained in a second crop? My answers: a. 10.2 b. 1.04 c. 1.04 am i correct?Explanation / Answer
a) Mass of acetanilide soluble = 200 mL * ( 5.10 g acetanilide /100 mL) =10.2 g . (b) At room temperature, mass of acetanilide soluble = 200 mL * (0.52 g acetanilide / 100 mL) =1.04 g . When it is cooled to room temperature (22 C), the excess massof acetanilide will be precipitated out. Hence mass of acetanilide obtained = 10.2 g - 1.04 g =9.16 g . c) The solution contains 1.04 g of acetanilide. It is concentrated to 50 mL and cooled to 0 C where solubilityis 0.10 g/100 mL So mass of acetanilide that will remain dissolved = 50 mL *(0.10 g / 100 mL) = 0.05 g . The remaining mass of acetanilide will be precipitated out i.e= 1.04 - 0.05 = 0.99 gRelated Questions
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