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Really dont understand this question The equilibrium constant Kp for the gas pha

ID: 687818 • Letter: R

Question

Really dont understand this question The equilibrium constant Kp for the gas phase thermaldecomposition of tert-butyl chloride is 3.45 at 500 K: (CH3)3CCL(g)yield (CH3)2=CH2 (g) +HCl (g) (a) calculate the value of Kc at 500 K (b) calculate the molar concentrations of reactants andproducts in an equilibrium mixture obtained by heating 1.00 mol oftert-butyl chloride in a 5.00L vessel at 500 K. Really dont understand this question The equilibrium constant Kp for the gas phase thermaldecomposition of tert-butyl chloride is 3.45 at 500 K: (CH3)3CCL(g)yield (CH3)2=CH2 (g) +HCl (g) (a) calculate the value of Kc at 500 K (b) calculate the molar concentrations of reactants andproducts in an equilibrium mixture obtained by heating 1.00 mol oftert-butyl chloride in a 5.00L vessel at 500 K.

Explanation / Answer

There's a small mistake in the species yeild it should be(CH3)2C=CH2. (a) Kp = Kc RT^n        3.45 = Kc (.0821 x500)1                         (n = 2-1=1)        Kc = 3.45/41.05             =0.084 moles/ltr. (b)        (CH3)3CCl ----------------->(CH3)2C=CH2    +   HCl initial conc.         1                                               0                           0 At EQ.         1-                                                                      no. of moles            1- /V                                      /V                      /V                    Kc=        (/V)2/[(1-)/V] neglecting 1-,,,,,,,,,,,,,,,,,,,,,,,                    Kc = 2 /V                     2 = 0.42                       = 0.648 eq concen. of reactant = 1- =0.352     eq concen. of product = =0.642.                        (a) Kp = Kc RT^n        3.45 = Kc (.0821 x500)1                         (n = 2-1=1)        Kc = 3.45/41.05             =0.084 moles/ltr. (b)        (CH3)3CCl ----------------->(CH3)2C=CH2    +   HCl initial conc.         1                                               0                           0 At EQ.         1-                                                                      no. of moles            1- /V                                      /V                      /V                    Kc=        (/V)2/[(1-)/V] neglecting 1-,,,,,,,,,,,,,,,,,,,,,,,                    Kc = 2 /V                     2 = 0.42                       = 0.648 eq concen. of reactant = 1- =0.352     eq concen. of product = =0.642.