Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Chlorite, ClO 2 - , han oxoanion ofchlorine, is used as a bleaching agent. Answe

ID: 689151 • Letter: C

Question

Chlorite, ClO2-, han oxoanion ofchlorine, is used as a bleaching agent. Answer a, b, and c. a. What is the geometry of the central Cl atom inClO2-? ___ tetrahedral ___ linear ___ trigonal planar ___octahedral ___ trigonal bipyramidal b. What is the hybridization of the Cl atom? ___ sp3 ___ sp2d ___sp3d___spd ___sp2 The trigonal planar molecule SO2 is shownbelow. (can't draw it) c. do the central atoms in ClO2-and SO2 have the same hybridization? ___ no ___ yes Chlorite, ClO2-, han oxoanion ofchlorine, is used as a bleaching agent. Answer a, b, and c. a. What is the geometry of the central Cl atom inClO2-? ___ tetrahedral ___ linear ___ trigonal planar ___octahedral ___ trigonal bipyramidal b. What is the hybridization of the Cl atom? ___ sp3 ___ sp2d ___sp3d___spd ___sp2 The trigonal planar molecule SO2 is shownbelow. (can't draw it) c. do the central atoms in ClO2-and SO2 have the same hybridization? ___ no ___ yes The trigonal planar molecule SO2 is shownbelow. (can't draw it) c. do the central atoms in ClO2-and SO2 have the same hybridization? ___ no ___ yes

Explanation / Answer

No. of hybrid orbitals ,H = (V+S-C+A) / 2 Where V = Valency of the central atom S = No. of single valency atoms attached to the centralatom C = No. of cations A = No . of anoins (1) ClO2 - No . of Hybrid orbitals , H = ( 7 + 0 - (-1) + 0 ) / 2                                         =4            --------- sp3 hybridization So the expected geometry is tetrahedral,but out of whichtwo are occupied by lone pairs.So the shape is linear. (2) No. of hybrid orbitals , H = ( 6 +0-0+0 ) / 2                                       = 3      ------------- sp2hybridization So , the hybridizations of the central atoms inClO2- and SO2 are different.
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote