Argon crystallizes in the face-centered cubic arrangement at 40 K.Calculate the

Question

Argon crystallizes in the face-centered cubic arrangement at 40 K.Calculate the mass of the unit cell of solid argon ingrams. Argon crystallizes in the face-centered cubic arrangement at 40 K.Calculate the mass of the unit cell of solid argon ingrams. Argon crystallizes in the face-centered cubic arrangement at 40 K.Calculate the mass of the unit cell of solid argon ingrams. Argon crystallizes in the face-centered cubic arrangement at 40 K.Calculate the mass of the unit cell of solid argon ingrams.

Explanation / Answer

Mass of an atom , m = Atomic mass / Avagadro number Avagadro number , N = 6.023 * 10^23 Plug the values we get m = 40 / 6.023 * 10^23                                       = 6.6412 * 10^-23 g For fcc arrangement No . of atoms in a unit cell =4 So , the mass of the unit cell , m' = No . of atoms inthe unit cell * mass of each atom,m                                                   = 4 * 6.6412 * 10^-23 g                                                    = 26.5468 * 10^-23g

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.