The rate constant for the reaction A--->B is 25/min at 298Kand 35/min at 350K. C
ID: 690976 • Letter: T
Question
The rate constant for the reaction A--->B is 25/min at 298Kand 35/min at 350K. Calculate the value of the rate constant at770K. Give your answer in /min. Answer: 100/min The rate constant for the reaction A--->B is 25/min at 298Kand 35/min at 350K. Calculate the value of the rate constant at770K. Give your answer in /min. Answer: 100/minExplanation / Answer
k = A*exp(-E/RT) (Arrhenius) k1 = A*exp(-E/RT1) => ln(k1) = ln(A)-E/RT1 ln(k2) = ln(A) - E/RT2 ln(k2/k1) = (-E/R)*(1/T2 -1/T1) note ln(k2) - ln(k1) = ln(k2/k1) ln(35/25) = (-E/R)*(1/350 - 1/298) = 0.336472237 -E/R = -674.88566 K k1 = A*exp(-E/R *1/T1) 25 = A*exp(-674.88566 / 298) A = 240.70998 Thus a T = 770K k = 240.70998 *exp(-674.88566 / 770) k = 100.194964 min^-1 k ~ 100 min^-1
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