The fermentation of glucose(C 6 H 12 O 6 ) produces ethyl alcohol(C 2 H 5 OH) an

Question

The fermentation of glucose(C6H12O6) produces ethyl alcohol(C2H5OH) and CO2. C6H12O6(aq) --> 2C2H5OH(aq) + 2 CO2(g) (a) How many moles of CO2 are produced when 0.250mol of C6H12O6 reacts in thisfashion?       _____ mol (b) How many grams of C6H12O6are needed to form 7.00 g of C2H5OH?       _____ g (c) How many grams of CO2 form when 7.00 g ofC2H5OH are produced?      _____ g The fermentation of glucose(C6H12O6) produces ethyl alcohol(C2H5OH) and CO2. C6H12O6(aq) --> 2C2H5OH(aq) + 2 CO2(g) (a) How many moles of CO2 are produced when 0.250mol of C6H12O6 reacts in thisfashion?       _____ mol (b) How many grams of C6H12O6are needed to form 7.00 g of C2H5OH?       _____ g (c) How many grams of CO2 form when 7.00 g ofC2H5OH are produced?      _____ g

Explanation / Answer

C6H12O6(aq) --> 2C2H5OH(aq) + 2 CO2(g) 1 mole of C6H12O6 produces 2moles of CO2 0.25 moles of C6H12O6produces 2* 0.25 = 0.5 moles of CO2 Molar mass of C2H5OH is = 2 * 12 + 5 *1 + 16 + 1 = 45 g Molar mass of C6H12O6 is = 6 * 12 + 12 * 1 + 6 * 16 = 180 g 180 g of C6H12O6 on reactionproduces 2 * 45 (=90) g of C2H5OH X g of C6H12O6 onreaction produces 7 g of C2H5OH X = ( 180 * 7 ) / 90     = 14 g Molar mass of CO2 is = 12 + 2 * 16 = 44 g 180 g of C6H12O6 on reactionproduces 2 *44(=88) g of CO2 14 g of C6H12O6 onreaction produces Y g of CO2 Y = ( 88*14 ) / 180    = 6.84 g of CO2

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