The fermentation of glucose(C 6 H 12 O 6 ) produces ethyl alcohol(C 2 H 5 OH) an

Question

The fermentation of glucose(C6H12O6) produces ethyl alcohol(C2H5OH) and CO2. C6H12O6(aq) --> 2C2H5OH(aq) + 2 CO2(g) (a) How many moles of CO2 are produced when 0.250mol of C6H12O6 reacts in thisfashion?      _____ mol (b) How many grams of C6H12O6are needed to form 7.00 g of C2H5OH?      _____ g (c) How many grams of CO2 form when 7.00 g ofC2H5OH are produced?     _____ g The fermentation of glucose(C6H12O6) produces ethyl alcohol(C2H5OH) and CO2. C6H12O6(aq) --> 2C2H5OH(aq) + 2 CO2(g) (a) How many moles of CO2 are produced when 0.250mol of C6H12O6 reacts in thisfashion?      _____ mol (b) How many grams of C6H12O6are needed to form 7.00 g of C2H5OH?      _____ g (c) How many grams of CO2 form when 7.00 g ofC2H5OH are produced?     _____ g

Explanation / Answer

C6H12O6(aq) --> 2C2H5OH(aq) + 2 CO2(g) Molar mass of glucose , C6H12O6 is = 6*12 + 12 * 1 + 6*16 =180 g Molar mass of C2H5OH = 2*12 + 5*1 + 16 + 1 = 46 g Molar mass of CO2 =12 + 2*16 = 44 g 1 mole of glucose produces 2 moles of CO2 0.25 moles of glucose produces 2* 0.25 = 0.5 moles ofCO2 180 g of glucose produces 2* 46 g of C2H5OH X g of glucose produces 7 g of C2H5OH X = ( 180*7) / ( 2*46)     = 13.7 g of glucose 7g of C2H5OH is produced from 13.7 g of glucose( by aboveresult) 180 g of glucose produces 2* 44 g of CO2 13.7 g of glucose producesY g of CO2 Y = ( 2*44*13.7 ) / 180     = 6.69 g of CO2 X g of glucose produces 7 g of C2H5OH X = ( 180*7) / ( 2*46)     = 13.7 g of glucose 7g of C2H5OH is produced from 13.7 g of glucose( by aboveresult) 180 g of glucose produces 2* 44 g of CO2 13.7 g of glucose producesY g of CO2 Y = ( 2*44*13.7 ) / 180     = 6.69 g of CO2

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