a) A graduated cylinder with 18 ml of water will contain18gm of water, which equ
ID: 691011 • Letter: A
Question
a) A graduated cylinder with 18 ml of water will contain18gm of water, which equals one mole of water molecules. If each ofthese water molecules were enlarged to the the size of a billiardball (2.25 inches in diameter ) were stacked side-by-side on afootball field using only the inbounds area (120.00 yards by 60.00yards), how high would a mole of billiard balls reach inKilometers? Assume that all billiard balls are identical. Show allcalculations. b) Traveling at the speed of light - how long would it take,in years, to reah the top the pile (of billiard balls)?. Show allcalculations. c) The ball each have a mass of 15.00 ounces each. If 16ounces equals 454 grams, what is the density of the rectangularprism that encloses the ball?. Show all calculation. a) A graduated cylinder with 18 ml of water will contain18gm of water, which equals one mole of water molecules. If each ofthese water molecules were enlarged to the the size of a billiardball (2.25 inches in diameter ) were stacked side-by-side on afootball field using only the inbounds area (120.00 yards by 60.00yards), how high would a mole of billiard balls reach inKilometers? Assume that all billiard balls are identical. Show allcalculations. b) Traveling at the speed of light - how long would it take,in years, to reah the top the pile (of billiard balls)?. Show allcalculations. c) The ball each have a mass of 15.00 ounces each. If 16ounces equals 454 grams, what is the density of the rectangularprism that encloses the ball?. Show all calculation.Explanation / Answer
cross sectional area of sphere (the cross sectional area determineshow many H2O molecules can fit on the inbound area) A = pi*r^2 = pi*(2.25 in / 2)^2 = 15.9043128 in^2 Area of football field = 120 yd *60 yd *(36 in / yd)^2= 9331200 in^2 # enlarged molecule per area = 9331200 in^2 / [15.9043128 in^2 /molecule] = 586708.783 molecules per area 1 mol of molecules = 6.022e23 molecules # of layers = 6.022e23 molecules / [586708.783 molecules/layer] = 1.02640359e18 layers each layer is the diameter thick, 2.25 inches height = 1.02640359e18 layers *(2.25 inches/layer) *(2.54 cm/ inch)*(1e-3 km / 100 cm) height = 5.86589652e13 km ~ 5.87 x 10^13 km b) speed of light = 3.0 x 10^8 m/s time = 5.87e13 km*(1s/3e8 m)*(1000 m/1km)*(1 hr/3600 s)*(1day/24 hr)*(1year/365.25 days) = 6.19596813 yr ~ 6.20 years c) volume = height *area = 5.87 x 10^13 km *(1000 m /1 km)*(120yd*60yd)*(36 in/yd)^2*(2.54 cm/in)^2 *(1 m/100 cm)^2 volume = 3.53133833e19 m^3 mass = 6.022e23 molecules *(15 oz /molecules)*(454 g/16 oz) =2.56311375e26 grams density = mass/volume = (2.56311375e26 grams/3.53133833e19 m^3)*(1 m /100 cm)^3 = 7.26 g/cm^3
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.