The reaction of equal molar amounts of benzene,C 6 H 6 , and chlorine, Cl 2 , ca

Question

The reaction of equal molar amounts of benzene,C6H6, and chlorine, Cl2, carriedout under special conditions, yields a gas and a clear liquid.Analysis of the liquid shows that it contains 64.03% carbon, 4.48%hydrogen, and 31.49% chlorine by mass and that is has a molar massof 112.5 g/mol. The molecular formula will be determined.
A) Determine the number of moles of carbon in a 100 gsample. B) Determine the number of moles of hydrogen in a 100 gsample C) Determine the number of moles of chlorine in a 100 gsample
My answers were wrong.
A) Determine the number of moles of carbon in a 100 gsample. B) Determine the number of moles of hydrogen in a 100 gsample C) Determine the number of moles of chlorine in a 100 gsample
My answers were wrong.

Explanation / Answer

The compound contained  64.03% carbon, 4.48%hydrogen, and 31.49% chlorine by mass. 64.03 g C is present in 100 g sample 4.48 g H is present in 100 g sample 31.49 g Cl is present in 100 g sample The number of moles of C = 64.03 g / 12.011 g/mol                                          =5.33 mol C The number of moles of H = 4.48 g / 1.008 g/mol                                          = 4.44 mol H The number of moles of Cl = 31.49 g / 35.45g/mol                                           = 0.888 mol Cl The ratio of the number of moles basing the smallestnumber of moles (here Cl - 0.888 mol) C / Cl = 5.33 mol C/0.888 mol Cl            = 6.00 mol C / 1 mol Cl H / Cl =4.44 mol H / 0.888 mol Cl            =5 mol H / 1 mol Cl The compound has 6.00 mol C and 5 mol H per 1 molCl

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