6a. How many moles of stomach acid would be neutralized by onetablet of Regualr

Question

6a. How many moles of stomach acid would be neutralized by onetablet of Regualr Strength Maalox that contains 600mg of calciumcarbonate? 6b. Assuming the volume of the stomach to be 1.0L, what willbe the pH change of the stomach acid resulting from the ingesgtionof one Regular Strength Maalox tablet? 6a. How many moles of stomach acid would be neutralized by onetablet of Regualr Strength Maalox that contains 600mg of calciumcarbonate? 6b. Assuming the volume of the stomach to be 1.0L, what willbe the pH change of the stomach acid resulting from the ingesgtionof one Regular Strength Maalox tablet?

Explanation / Answer

The answer is 1.2 X10^-2
6b. For thisquestion, you need the starting pH and the volume of the stomach.According to wikipedia.org, the pH of the stomach is 1.2. pH =-log(H+). This is the same as 10^ -1.2 which is .0631M for stomachacid concentration. This means .0631 moles/liter. Assuming a volumeof one liter, (you will have to adjust if the volume is different)subtract the moles of HCL that are neutralized by the CaCO3 (.012)from .0631 and you get .051 M HCl. Now you need to convert thisback to the pH scale by taking the negative log of .051, which =1.3. So, the change in pH is from 1.2 to 1.3.

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