Specitic Heat in his problero answers are requested tovee sigwicent digrs for gr

Question

Specitic Heat in his problero answers are requested tovee sigwicent digrs for gradng pwpose8. The ue number of signiicant digts may be more or less The heat capacity of an object indcates how much energy that object can absorb for a given increase in that object's temperature. In a system in which two objects of dTerent temperatures come into contact with one another, the warmer object wil cool and the cooler object will warm up uil the sysiem is at a single equibrium Part A A vclume of 100. L of O is initialy at room temperaturo (22.00"C). A chilled steel rod at 2.00Ci placed in the wator. If the final lomporature of the system is 21.0Cwhat is the mass of the stool bar? Use the follicwing values Note the diference between the tems moiar heat capacity, which has unts of J/(nol . °C). and specie heer, which has units of JKe·"c). specitic heat of water4.18 J/E-C specific heat of stee1-0.452 J/(g·"C Express your answer to throo significant tigures and include the appropriato unts Hints mass of the steel- 75.2 My Answers Give Up Incorrect; Try Again; 6 attempts remaining Part B The speoific heat of water is 4.18J/ C).Calcutate the molar heat capacity of water Express your answer to three significant figures and include the appropriate units molar heat capacity forwater 75.2 J Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining

Explanation / Answer

A)

Let us denote steel by symbol 1 and water by symbol 2

m1 = to be calculated

T1 = 2.0 oC

C1 = 0.452 J/goC

m2 = 100.0 g

T2 = 22.0 oC

C2 = 4.18 J/goC

T = 21.0 oC

we have below equation to be used:

heat lost by 2 = heat gained by 1

m2*C2*(T2-T) = m1*C1*(T-T1)

100.0*4.18*(22.0-21.0) = m1*0.452*(21.0-2.0)

m1= 48.7 g

Answer: 48.7 g

B)

specific heat capacity = 4.18 J/g.oC

molar mass of H2O = 18 g/mol

use:

molar heat capacity = specific heat capacity*molar mass

= 4.18 J/g.oC * 18 g/mol

= 75.2 J/mol.oC

Answer: 75.2 J/mol.oC

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