e terrorist group CGB (Chemists Gone Bad) has developed a substance that looks l

Question

e terrorist group CGB (Chemists Gone Bad) has developed a substance that looks like gold, feels like gold, has the same density as gold, and even tastes like gold (just kidding on the last one). They are attempting to take over the world by using this counterfeit gold to buy everything. You, a world famous chemist, have been hired by the governments of the world to foil these scoundrels who have given chemistry a bad name. It is your job to prove that their substance is not gold. Genius that you are, you decide first to see if this substance has the same specific heat as gold does. You take a 23 1.6 g piece of the fake gold, heat it to 95.0°C, and then drop it into 100.0 g of water which is at 25.00. The final temperature of the water and the fake gold is 30.0°C. What is the specific heat of the fake gold? How does this conmpare to the specific heat of gold, 0129 J/g ?

Explanation / Answer

mass = 231.6 g of sample

initial temperature = 95 C

final temperature = 30 C

suppose specific heat =s

so total heat lost by the sample

m * s * change in temperature = 231.6 * s * (95-30)

231.6 * s * 65

now heat gained by the water

mass = 100 g

initial temperature = 25 C

final temperature = 30 C

specific heat of water = 4.186 J/g C

now heat gained

m * s * change in temperature of water

100 * 4.186 * (30-25)

418.6* 5 = 2093 j

it is equal to heat lost by sample

231.6 * s * 65 = 2093

s = 2093/231.6 * 65

s = 0.139 j /g C

here the specific heat of sample is diiferent from pure gold . now we can distinguish between pure and fake gold .

pure gold specific density = 0.129 j/g C

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