When chemists work with solid materials, we simply weigh out amounts of solid re

Question

When chemists work with solid materials, we simply weigh out amounts of solid reagents and calculate mole amounts when stoichiometry, However, when we dissolvea solid (also known as a solute) in a solvent to form a solution, the solute becomes evenly throughout the solution and we need to know how many moles of solute are present in a particular volume of solution. thinking about 1st attempt Part 1 (0.3 point) hl see periodicTable ’See Hint A solution is created by dissolving 10.0 grams of ammonium chloride in enough water to make 325 mL of solution. Howm moles of ammonium chloride are present in the resulting solution? any moles of NH C

Explanation / Answer

part 1)

mass of NH4Cl = 10.0 g

moles of NH4Cl = 10.0 / 53.49 = 0.187

volume of solution = 325 mL

moles of NH4Cl = 0.187

part 2)

Molarity = moles / volume

             = 0.187 / 0.325

Molarity = 0.575 M

part 3)

moles = 0.0500 mol

volume = 0.0500 / 0.575

volume of solution = 0.0869 L

volume = 86.9 mL

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