f products reactants reaction progress 6) According to the diagram above, the fo
ID: 693195 • Letter: F
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f products reactants reaction progress 6) According to the diagram above, the forward reaction is nonspontaneous at d and e, and spontaneous at f. nonspontaneous at d, at equilibrium at e, and spontaneous at f cnontaneous at d, at equilibrium at e, and nonspontaneous at f. spontaneous at d, e, and f 7) According to the diagram above, G" is positive and the equilibrium composition is rich in products. 3)AG is positive and the equilibrium composition is rich in reactants. C AG is negative and the equilibrium composition is rich in products. D) AG° is negative and the equilibrium composition is rich is reactants. Chapter 21 48) Consider the following redox equation Mn(OH)2(s) + MnO4-(aq) MnO42-(aq) (basic solution) When the equation is balanced with smallest whole number coefficients, what is the coefficient for OH (a) and on which side of the equation is OH (a) present? A) 4, reactant side B) 4, product side C) 6, reactant side D) E) 6, product side None of these choices is correct. Complete and balance the following redox equation using the set of smallest whole number coefficients. Now sum the coefficients of all species in the balanced equati (Remember the coefficients that are equal to one.) The sum of the coefficients is 9) BrO3(aq) + Sb3+(aq) Br(aq) + Sb5+(aq) (acidic solution)Explanation / Answer
48)
The reaction is split into two half reactions:
Mn(OH)2 MnO42- MnO4- MnO42-
Oxygen atoms are balanced as: oxygen atoms are in balanced state.
Mn(OH)2+2OH- MnO42- MnO4- MnO42-
Hydrogen atoms are balanced as:
Mn(OH)2+2OH- MnO42-+4H2O
Mn(OH)2+2OH- +4OH- MnO42-+4H2O
Charge is balanced as: charge is balanced as:
Mn(OH)2+6OH- MnO42-+4H2O+5e- MnO4- +e- MnO42-
Equalizing the charges and adding both the equations as:
Mn(OH)2+6OH- MnO42-+4H2O+5e-
5MnO4- +5e- 5MnO42-
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Mn(OH)2+5MnO4- +6OH- 6MnO42-+4H2O
6OH- are added on the reactant side. Option C) is correct.
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