10. Calculate the percent oxalic acid dihydrate in an \'unknown if the sample ma

Question

10. Calculate the percent oxalic acid dihydrate in an 'unknown if the sample mass was 1.0994g and was titrated against 2.33mL of 0.327M KOH (10 points). a. 5.28% b. 3.23% c. 4.37% d. 5.3% 11. If37.31 mL of 0.0200 M oxalic acid reacted with 17.65 mL of KMnOs, what is the molarity of the KMnO4 solution? (10 points) a. 0.0169 M b. 0.0191 M c. 0.106 M 12. How do you prepare 600 mL of 0.03 M KMnO&from; 0.20 M KMn04? (10 points) a. Take 110 mL of 0.40 M KMn0, stock solution and dilute to a final volume of 600 ml b. Take 50 mL of 0.40 M KMnOs stock solution and dilute to a final volume of 600 mL c. Take 80 mL of 0.40 M KMnOs stock solution and dilute to a final volume of 600 ml d. Take 90 mL of 0.20 M KMnO& stock solution and dilute to a final volume of 600 mL

Explanation / Answer

Ans 10. b) 3.23 %

The reaction is given as :

(COOH)2 + 2KOH = K2(COO) + 2H2O

No. of moles of KOH = 0.00233 x 0.327 = 0.00076191 moles

SO number of moles of acid = 0.00076191 / 2 = 0.000380955 moles

Mass of acid = 0.000380955 x 90.03 = 0.0343 g

Mass % = ( 0.0343 / 1.0994) x 100

= 3.23 %

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