University of Oklahoma × C) Topic: LR Peer Review O saplingleaming.com/ibiscms/m

Question

University of Oklahoma × C) Topic: LR Peer Review O saplingleaming.com/ibiscms/mod/ibi5Nie w.php?id-3871 612 Sapling Learning macmilan learning Jump to.. Andrea Brisby Question 8 of 8 Available From: 11/27/2017 06:00 PM Due Date: Points Possible: 3 Grade Category: Extra Credit 12/4/2017 11:55 PM Consider this reaction data If you were going to graphically determine the activation energy 3 100 this reaction, what points would you plot? products T(K) (5) point 1: To avoid rounding errors, use at least attempt, 0% penalty. 0.380 Solutions After Due Date 925 0.714 three significant figures in all values. 6 0 You can check your answers. You can view solutions after the due date You have five attempts per question. There is no penalty for incorrect answers. point 2: Determine the rise, run, and slope of the line formed by these points. rise slope 0 eTextbook Number OHelp With This Topic What is the activation energy of this reaction? O Web Help & Videos Number J mol O Technical Support and Bug Reports Previous Check Answer Nextx Hin © 2011-2017 Sapling Learning, Inc. about u | careers | privacy policy | tams of use | contact us | help 3-54 PM Type here to search ^ 12/4/2017

Explanation / Answer

We need to plot lnK on y axis and 1/T on x axis

K = 0.38

ln K = ln (0.38) = -0.96758

T = 225.0

1/T = 0.00444

point 1 is:

x = 0.00444

y = -0.96758

K = 0.714

ln K = ln (0.714) = -0.33687

T = 825.0

1/T = 0.00121

point 2 is:

x = 0.00121

y = -0.33687

----------------------------------------------------------------------------

rise = (y1-y2) = -0.96758 - -0.33687 = -0.63071

rise = (X1-X2) = 0.00444 - 0.00121 = 0.00323

slope = rise/run

= -0.63071/0.00323

= -195.12644

----------------------------------------------------------------------------

use

slope = - Ea/R

= -195.12644 = -Ea/8.314

Ea = 1622 J/mol

Feel free to comment below if you have any doubts or if this answer do not work. I will edit it if you let me know

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