help please Part A Calculating Equilibrium Constants Phosgene (carbonyl chloride

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Part A Calculating Equilibrium Constants Phosgene (carbonyl chloride), COCl, is an extremely toxic gas that is used in manufacturing certain dyes and plastics. Phosgene can be produced by reacting carbon monoxide and chlorine gas at high temperatures: The equilibrium constant, K, of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium. CO(g) + Cl (g) COCl2(g) Carbon monoxide and chlorine gas are allowed to react in a sealed vessel at 458 C.At equilibrium, the c obtained were measured and the following results For a gaseous reaction with the general form Partial Pressure atm) 0.700 1.29 Gas the Ke and Kp expressions are given by CO Al B COC0.170 KPb) p-(Pa)"(Ps) What is the equilibrium constant, Kp. of this reaction? The subscript cor p indicates whether Kis expressed in terms of concentrations or include a term for any pure solids or liquids that may be involved in the reaction. pressures. Equilibrium-constan t expressions do not Express your answer numerically Hints K, 0.188 Submit My Answers Givo Up Correct Deriving concentrations from data In Part A ou were given the equilibrium pressures, which could be plugged direct y into the ormula r K In Part B how ever, you will be given initial concentrations and only one equilbrium concentration. You must use this data to find all three equil ibrium concentrations before you can apply the formula for K Part B The following reaction was performed in a sealed vessel at 735 C H2(g) +I2()2Hg) Initially, only H2 and I2 were present at concentrations of H2]-3.50Mand 23.00M. The equilibrium concentration of I is 0.0700 M. What is the equilibrium constant, K, for the reaction at this temperature? Express your answer numerically. Hints

Explanation / Answer

CO(g) + Cl2(g) --------> CoCl2(g)
Kp = PCOCl2/PCO*PCl2
    = 0.17/0.7*1.29   = 0.188 >>>>answer

   H2(g)+ I2(g) ---------> 2HI(g)
I    3.5      3               0
C    -2.93     -2.93         2*2.93
E    0.57 0.07         5.86
{H2] = 0.57M
[I2]   = 0.07M
[HI] = 5.86M
        Kc = [HI]^2/[H2][I2]
            = (5.86)^2/0.57*0.07   = 860.64>>>>answer

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