Can I get some help with this?? Thanks!! Can I get some help with this?? Thanks!
ID: 695996 • Letter: C
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Can I get some help with this?? Thanks!! Can I get some help with this?? Thanks!! t For the fslhowing pairs of elementsions, civle the correst element that fits the description for periodic wens (21) a Cor K has a greater metallic characten. Clor Be has a lower first lonization energy H e Oor S has a larger atomic radius d. N or O has a greater fiest ionisation energy (E) e Na or Mg has a greater metallic character t Por Cl has a lower first ionization energy (E) s Oor Fhas a larger atomic radius h. Sor CI has a more exothermic electron affinity i Ct or CT has a lower first ionization energy (IE j. Ne or Na has a larger atomic radius k. Ne or F has a larger atomic radius. L Si or S has a greater effective nuclear charge. m. Ne or Ar has a greater density n. The IEs of Mg or IE of Al is greater 14. Write a balanced chemical equation for each of the following reaction description: 4) a. Solid lithium reacting with liquid bromine. b. Solid potassium reacting with liquid water. .page total: 25 test total: 103Explanation / Answer
a) The metallic character increases down the group and decreases accross a period from left to right. Thus,
Cs has greater metallic character.
b) The ionization energy decreases down the group as atomic radius increases. Thus Br has lower IE1 value.
c) The metallic radius increases down the group and nuclear force of attraction decreases. Thus, S has larger atomic radius.
d) Nitrogen has the greater first ionization energy as the p subshell of N-atom is half filled and is thus more stable than an O-atom which has 4 electrons in its valence p-subshell.
e) The metallic character increases down the group and decreases accross a period from left to right. Thus,
Na has greater metallic character.
f) The ionization energy decreases down the group as atomic radius increases and increases from left to right across a period. Thus P has lower IE1 value.
g) The metallic radius decreases across the period from left to right and nuclear force of attraction increases. Thus, O has larger atomic radius.
2) 2Li(s) + Br2(g) ----> 2 LiBr
2K(s) + 3H2O(l) ------> 2KOH(aq) + 2H2(g)
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