15. Consider the reaction CO(g) + ½ Odg--COdg) at equilibrium. What will happen

Question

15. Consider the reaction CO(g) + ½ Odg--COdg) at equilibrium. What will happen if the sure is increased at constant temperature by adding an inert gas? a. Nothing will happen. b. The reaction will shift to the left (reactants side.) c. The reaction will shift to the right (products side.) press 16. AG for a reaction is 1.9 kJ at 298 K. AH is 3.6 kJ. Which of the following expressions can be solved to find AG at 545 K? x 1.9kJ 545K 298K 545K 98K 545K-208K 36k ,1.9 = 3.6 298K 545K x3.6k/ 4K 298K x1.9k.J 545K 298 K = 1.9k/1545K-298K -- 298K 545 K

Explanation / Answer

Ans 15 : c) the reaction will shift to the right (products side)

The system at equillibrium always tries to nullify the effect of external conditions on it by moving in either of its direction.

Since here the pressure is lower in the products side , increasing the pressure by addition of inert gas , will shift the equillibrium to right , so that equillibrium can be re-estabilished.

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