i need the solution CHEM 30A NAME FINAL EXAM g and 25 °C, a gas sample has a vol
ID: 696659 • Letter: I
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i need the solution
CHEM 30A NAME FINAL EXAM g and 25 °C, a gas sample has a volume of 2270 mL What is the re constan (in mmHg) at a volume of 1250 mL and a temperature of 175 °C, if the moles a A) 1560 mmHg B) 210. mmHg C) 700. mmHg D) 690. mmHg E) 470. mmHg Answer: A 15) W hat volume would a 0.250 mole sample of H2 gas occupy, if it had a which has a 1.70 atm, and a temperature of 35 °C? A) 0.269 L B) 0.423 L C) 1.25 L D) 3.72 L E) 283 L Answer: D 16) Which of the following gives the balanced equation for this reaction? KyPO4 + Ca(N103)2 Ca3(PO4)2 + KNO3 A) KPO4+CaNO3+ KNO3 B) K3 PO4 + Ca(NO3)2 Ca3(PO4)2 + 3KNOg C) 2KgPO4 + Ca(NO3)2 Ca3(PO4)2 + 6KNOg D) 2KgPO4 + 3Ca(NO3)2 Ca3(PO4)2 + 6 KNO3 E) K3PO4 + Ca(NO3)2 Ca3(PO4)2 + KNO3 Answer: D 17) How many grams of H20 are needed to produce 150 g of Mg(OH)2? M83N2(s) + 6H20(1) 3Mg (OH)2(s) + 2NH3(s) A) 46 g B) 18g C) 130 g D) 93 g E) 23 g Answer DExplanation / Answer
14. P1V1/T1 = P2V2/T2
P1 = 570mmHg
V1 = 2270mL
T1 = 25 = 298K
P2 = ?
V2 = 1250mL
T2 = 175= 448K
P1V1/T1 = P2V2/T2
P2 = P1V1T2/T1V2
P2 = 570mmHg*2270mL*448K / 298K*1250mL
P2 = 1560mmHg
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