17. How many atoms of oxygen are in 12.99 g of nickel(I) nitrate? A) 2.569 x 102

Question

17. How many atoms of oxygen are in 12.99 g of nickel(I) nitrate? A) 2.569 x 1023 B) 1.944 x 1023 C) 1.308 x 1023 D) 1.284 x 1023 E) 2.141 x 1023 18. The hybridization of the central atom in XeFst1 is A) sp B) spa C) sp3 D) dsp3 E) d2sp3 19. Which list of compounds has them listed from highest to lowest mp A) CaS > NaCl> H20> CH3CI > Br2> He B) NaCI> Cas > CH3Cl > H20 > Br2 > He C) Cas >NaCI> CH3CI> H20> Br2>He D) He > Br2> H2O> CH3CI>NaCI> Cas E) Cas >NaCI> CHaCI> H20> He > Br2

Explanation / Answer

17) nickel nitrate is Ni(NO3)2

Thus one mole of Nickel nitrate has 6 moles of oxygen atoms

molar mass of nickel nitrate =182.7 g/mol

moles of sample = mass /molar mass

= 12.99/182.7

=0.0711

moles of O atoms in the sample = 6 x 0.0711 mol

atoms of O in the sample = moles x Avogadro number

= 6x0.0711 x 6.022 x1023 atoms

= 2.569x1023

OPTION A

18)

Xe has 8 valence electrons

XeF5+ has 5 bond pairs and one lone pair of electrons

so the hybridisation is sp3d2 (octahedral)

option E

19) OPtion A

CaS has Ca+2 and S-2 ions , an ionic compound iwht high charge, higher lattice energy, thus highest m.p.

NaCl is ionic

H2O is polar covalent compound

CH3Cl is polar covalent (less than water)

Br2 is non-polar covalent compound

He is monoatomic noble gas with very less forces of attraction.

Thus expalins the order.

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