During the experiment Chemcal s D determined for the reaction SeI n of a Rate La

Question

During the experiment Chemcal s D determined for the reaction SeI n of a Rate Law the rate law, rate kETS an 250a was deteried From the data shown t ouud be 0.042 0.004 2.1010 Reaction Rate SHEET 0042 10.042 11.55 The order of the reaction rate with respect to so The order of the reaction rate with respect to Sia. b) The order of the reaction rate with respect ) The order of the reaction rate with respect to Iv. What is the correct exper number of significant figures in the answer determined vakue for the enthalpy of a reac to the percent difference calculation for the tion? CAUTION: Be thorough in your analysis of 378 KI/mol-94.771/mol 9477 K1/mol x 100% b) 2 26) What infor mation can be determined for the reaction A + B c, given the rate law: ' a) The rate law is incomplete without expressing the order with respect to reactant B. b) The product C must be a solid given that it is not included in the rate law. ) The reaction rate with respect to reactant B is zeroth order. d) Both b and c are corect. Use the rate law equation in Question 26 to determine the rate constant (k) for the reaction. reaction was 8.62 x 10 M/sec and initial concentration of reactants a) 1.2 x 10 sec b) 14 x 10 sec c) 1.0x 10 sec d) 7.2 x 10 sec The rate of the A and B were 0.12M and 0.044M respectively. to the rate of the reaction if the 26) For the reaction and rate law equation in Question 26, what would happen concentration of reactant A was doubled? a) The rate would double. b) The rate would be cut in half c) The rate would increase by a factor of 4. d) There will be no effect on rate 29) What value represents an acceptable reading of this thermometer to the correct number of sig nant figures? a) 924 b) 87.5 c) 87.45C d) 92.38C to 454

Explanation / Answer

24) Ans = d

Given reaction is I- + S2O82- ----------> I3- + 2SO42-

A + B -----------> C + D

rate = k [A]x [B]y   

   k = rate constant , x = order of the reaction with respect to I- , y = order of the reaction with respect to S2O82-

From trial 1,

2.1 x 10-5 = k [0.042]x [0.084]y   ------- Eq (1)

From trial 2,

1.05 x 10-5 = k [0.042]x [0.084]y --------Eq (2)

Do Eq(1)/Eq(2),

(2.1 x 10-5/1.05 x 10-5) = (k/k) (0.042/0.042)x (0.084/0.042)y

2 = 1x x (2)y --------Eq(3)

21 = 2y

y = 2

Therefore,

order of the reaction with respect to S2O82- = 2

---------------------------------------------------------------

Therefore,

ans = d

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