The data for the dS values is not visible in the pic, so I am providing you the
ID: 700059 • Letter: T
Question
The data for the dS values is not visible in the pic, so I am providing you the equations you need to solve this question.
(a)
Free energy change = dG = dH - T*dS
Here,
dH = dHprod - dHreac = (dHH2S + dHCu) - (dHH2 + dHCuS)
Similarly,
dS = dSprod - dSreac = (dSH2S + dSCu) - (dSH2 + dSCuS)
Put the values for dH and dS into the equation above, and put T = 298 K to calculate the value of dG.
(b)
If in part (a) above, the value of dG is negative, then it will proceed sponateously in the direction given.
If dG > 0, then reaction will not be spontaneous.
(c)
Use the following equation:
dG = -R*T*ln(*K)
Putting values:
dG = -8.314*298*ln(K)
Put the value of dG calculated in part (a) above and calculate the value of equilibrium constant K, at the given temperature.
Hope this helps !
Explanation / Answer
A (N,S) 20.6 k 4 points Caleulate the tandard re energy of the waction AG b- Will the reaction proceeds spontaneously at 298 K? Why? 2 point e- Calculate the equilibrium constant for the reaction at 298 K. 4 p
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