Ka1 = 4.3*10^-7 Ka2 = 4.8*10^-11 H2CO3 + H2O ---------------------> H3O^+ (aq) +
ID: 700179 • Letter: K
Question
Ka1 = 4.3*10^-7
Ka2 = 4.8*10^-11
H2CO3 + H2O ---------------------> H3O^+ (aq) + HCO3^- (aq)
I 0.13 0 0
C -x +x +x
E 0.13-x +x +x
Ka1 = [H3O^+][HCO3^-]/[H2CO3]
4.3*10^-7 = x*x/0.13-x
4.3*10^-7*(0.13-x) = x^2
x = 0.00024
[H3O^+] = x = 0.00024M
[OH^-] = Kw/[H3O^=]
= 1*10^-14/0.00024 = 4.16*10^-11M
[HCO3^-] = x = 0.00024M
HCO3^- (aq) + H2O -------------------> CO3^2- (aq) + H3O^+ (aq)
Ka2 = [CO3^2-][H3O^+]/[HCO3^-]
4.8*10^-11 = [CO3^2-]*0.00024/0.00024
[CO3^2-] = 4.8*10^-11 M
Explanation / Answer
Calculate the concentration of all species in a 0.130M solution of H2CO3. [H2CO3], [HCO3^-] , [CO3^2-], [H3O^+], [OH^-] Please show work Calculate the concentration of all species in a 0.130M solution of H2CO3. [H2CO3], [HCO3^-] , [CO3^2-], [H3O^+], [OH^-] Please show work Please show workRelated Questions
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