We shall use the ideal gas law to find out the mole(s) of CO 2 evolved. We need

Question

We shall use the ideal gas law to find out the mole(s) of CO2 evolved. We need to convert the pressure in atm, the volume in L and the temperature in K as below.

Trial 1

Trial 2

Pressure of dry CO2 (g) (atm)

(738.6 mmHg)*(1 atm/760 mmHg) = 0.9718 atm

(739.3 mmHg)*(1 atm/760 mmHg) = 0.9728 atm

Volume of CO2 (g) collected (L)

[(26.0 – 4.0) mL]*(1 L/1000 mL) = 0.022

[(23.5 – 10.5) mL]*(1 L/1000 mL) = 0.013

Temperature of water (K)

(24 + 273) K = 297

296.5

Moles of CO2 (mol) n = PV/RT

(0.9718 atm)*(0.022 L)/(0.082 L-atm/mol.K).(297 K) = 8.779*10-4

(0.9728 atm)*(0.013 L)/(0.082 L-atm/mol.K).(296.5 K) = 5.2019*10-4

Trial 1

Trial 2

Pressure of dry CO2 (g) (atm)

(738.6 mmHg)*(1 atm/760 mmHg) = 0.9718 atm

(739.3 mmHg)*(1 atm/760 mmHg) = 0.9728 atm

Volume of CO2 (g) collected (L)

[(26.0 – 4.0) mL]*(1 L/1000 mL) = 0.022

[(23.5 – 10.5) mL]*(1 L/1000 mL) = 0.013

Temperature of water (K)

(24 + 273) K = 297

296.5

Moles of CO2 (mol) n = PV/RT

(0.9718 atm)*(0.022 L)/(0.082 L-atm/mol.K).(297 K) = 8.779*10-4

(0.9728 atm)*(0.013 L)/(0.082 L-atm/mol.K).(296.5 K) = 5.2019*10-4

Explanation / Answer

ulation of mass of CaCO, sample for analysis (from Prelaboralory Assighmet, questiol 2). 28.44A-C 3.s Trial 1 Trial 2 nown sample no Mass of sample (g) Mass of generator + sample before reaction (g) Instructor's approval of apparatus Determination of Volume, Temperature, and Pressure of the Carbon Dioxide Gas Initial reading of volume of water in CO.-collecting ml 16.6m 54 93 Sni graduated cylinder (mL) Final reading of volume of water in CO,-collecting graduated cylinder (mL.) olume of CO,(g) collected (L) Temperature of water C) Barometric pressure (torr) apor pressure of H,O at "C (orr) Pressure of dry CO,(g) (torr) mount of Carbon Dioxide Gas Evolved Mass of generator + sample after reaction (g) Mass loss of generator mass CO2 evolved(g) Moles of CO, evolved (mol) oadL Experiment 13 1 163

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