We receive a shipment from one of three warehouses W1, W2, and W3, where each wa
ID: 3207430 • Letter: W
Question
We receive a shipment from one of three warehouses W1, W2, and W3, where each warehouse is equally likely and: • Warehouse 1 has 50 parts, 5 of which are defective. • Warehouse 2 has 40 parts, 10 of which are defective. • Warehouse 3 has 20 parts, 10 of which are defective.
(a) A shipment of 10 parts arrives and I test the first part. What is the probability that part is defective?
(b) A shipment of 10 parts arrives and I test all 10 parts. What is the probability that exactly 8 of the parts are defective?
(c) A shipment of 10 parts arrives and I test all 10 parts. I find exactly 8 defective parts.
• What is the probability the shipment came from warehouse W1?
• What is the probability the shipment came from warehouse W2?
• What is the probability the shipment came from warehouse W3?
(d) A shipment of 10 parts arrives and I test the first part, finding that it is defective. Given this information, what is the probability that I find exactly 8 defective parts (including the one already tested) in that shipment?
Explanation / Answer
A) P( defective 1st part) = (1/3)x(5/50) + (1/3)x(10/40) + (1/3)x(10/20)
= 0.2833
B) P(8 defective out of 10) = 0 + P(8 defective from W2) +
P(8 defective from W2)
= 0 + 10C8 x 0.258 + 0.752 + 10C8 x 0.58x0.52
0.0004 + 0.0439= 0.0443
C) P(shipment came from W1) = 0
P( shipment came from W2) = 0.009
P(shipment came from W3) = 0.991
D) P(8 parts defective | first part defective)
= P(8parts defective and 1st part defective)/P(first part defective)
= (0+ 0.25 x 9C7x0.257x0.752 + 0.5x9C7x0.57x0.52)/0.2833
= 0.125
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