C2H4 + Cl2 -----> C2H4Cl2 Molar mass ( g/mol) 28 71 99 1 mole = 28 g of C2H4 rea

Question

                                C2H4   + Cl2    ----->    C2H4Cl2

Molar mass ( g/mol)   28           71                  99

1 mole = 28 g of C2H4 reacts with 1 mole = 71 g of Cl2

            11.22 g of C2H4 reacts with M g of Cl2

M = ( 11.22x71)/28 = 28.45 g of Cl2

So 35.45 - 28.45 = 7.00 g of Cl2 left unreacted , so Cl2 is the excess reactant

Since all the mass of C2H4 completly reacted it is the limiting reactant

1 mole = 28 g of C2H4 reacts witCl2 produces 99 g of C2H4Cl2

             11.22 g of C2H4 produces ( 11.22 x 99)/28 = 39.67 g of C2H4Cl2

So for 100 % of the yield the mass of 1,2-dichloroethane produced is 39.67 g

If the percent yield of the reaction is 50% then the mass of reactant left is 35.45 - 28.45 = 7.00 g of Cl2

Explanation / Answer

Page 8 of 8 (10 points) The dry-cleaning solvent 1.2 dichloroethane (also called ethylene chloride), CHAC, is ired by reaction of 11.22 g of ethylene (C2H4) with 35.45 g of Cl2. C2H4 +Cl2 C2H4C12 roduced? a) If the percent yield is 100.0%, after the reaction, how many grams of the product of 1,2 dichloroethane (b) If the percent yield is 50.00%, after the reaction, what is the total mass of the reactants left over? folar mass of CH4 28.05 g/mol; Molar mass of Cl2-70.90 g/mol; Molar mass of C2H4Cl2 98.95 gmol)

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