Please show all work and all steps a.)Write the rate laws for the rate of consum

Question

Please show all work and all steps

a.)Write the rate laws for the rate of consumption of the reactant species i, -ri, for reactions (i.), (ii.), and (iii.) assuming that each reaction follows an "elementary rate law". If there are more than 1 reactant species, take reactant i to be the first reactant that is listed in the equation. (i.) 2A BIC, b.) Now consider the case where reaction (i.) is described by a non-elementary power law expression where the reaction order with respect to species A (,) is 1.5. If you wish to express-4 for reaction (i) as a volumetric reaction rate in units of [] mole (L-s), and the concentration of A is given in units of mole/L, what will be the units of the forward rate constant, kf? (ii) A B 2C, (iii) A -B + C

Explanation / Answer

Part a

For elementary reaction

(i) this is an reversible reaction

Forward reaction is

2A - - - > B + C

Forward rate of reaction in terms of reactant A

rA = - k [A]2

Negative sign represents the consumption of A

Reverse reaction is

B + C - - - > 2A

rA = +k' [B] [C]

Positive sign represents the formation of A

Overall reaction rate of A

rA = - k [A]2 + k' [B] [C]

Where k is the rate constant of forward reaction and k' is the rate constant of backward reaction.

(ii) the given reaction

A + B - - - > 2C

rate of reaction in terms of reactant A

rA = k [A] [B]

rate of reaction for B will be same as A.

(iii)

this is an reversible reaction

Forward reaction is

A - - - > B + C

Forward rate of reaction in terms of reactant A

rA = - k [A]

Negative sign represents the consumption of A

Reverse reaction is

B + C - - - > A

rA = +k' [B] [C]

Positive sign represents the formation of A

Overall reaction rate of A

rA = - k [A]+ k' [B] [C]

Where k is the rate constant of forward reaction and k' is the rate constant of backward reaction.

Part b

For reaction (i)

this is an reversible reaction

Forward reaction is

2A - - - > B + C

Forward rate of reaction in terms of reactant A if order = 1.5

rA = - kf [A]1.5

Negative sign represents the consumption of A

[Mol/L] *[1/s] = k [mol/L]1.5

kf = [Mol/L]0.5 *[1/s]

kf = mol0.5 - L-0.5 - s-1

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