3. For the next 4 reactions, Cl2 (aq)+H2 (aq) 2 HCI (aq), consider the following

Question

3. For the next 4 reactions, Cl2 (aq)+H2 (aq) 2 HCI (aq), consider the following table of equilibrium constants. what is NH3 (aq) + H20 (4 NH4+ (aq) + OH' (aq), the Kee of each of the following | H2O(4=H' (aq) +OH-(aq), manipulated reactions? Kea 16.0 Keq-1.8x 10-5 Keg 1.0 x10-14 a. HCl (aq) ½ Cl2 (aq) + ½ H2 (aq) b. H(aq)OH (aq) H,0 (4 c. 3 NH, (aq)+3 H,o (43 NH (aq)+3 OH (aq) d. NH, (aq)+ H' (aq) NH, (aq) 4. Calcium carbonate (limestone) can decompose according to the following reaction. Suppose the Kp at a certain high temperature is 1.20. What will be the equilibrium pressure of CO, (g) if a sufficiently sizable slab of limestone is placed in a reaction chamber CaCO, (s) Cao (s)+ co, (g) 5. THE GREAT HALL OF LE CHATELIER'S PRINCIP reasonable rate in the presence of a transition metal catalyst (such as iron or nickel) accordine LE: Carbon monoxide can be decomposed at a

Explanation / Answer

Ans 3

Part a

Write the reverse of the first given reaction

2HCl = Cl2 + H2, K1 = 1/16

Now divide the equation by 2

HCl = 1/2 Cl2 + 1/2 H2

Keq = (K1)1/2  = (1/16)0.5 = 1/4

Part b

H2O = H+ + OH- K2 = 1 x 10^-14

Write the reverse of third equation

H+ + OH- = H2O

Keq = 1/K2 = 1/(1 x 10^-14) = 1 x 10^14

Part C

Multiply by 3 in the second equation

3 NH3 + 3 H2O = 3 NH4+ + 3 OH-

Keq = (1.8 x 10^-5)3 = 5.832 x 10^-15

Part d

Write the second equation as it is

NH3 + H2O = NH4+ + OH- K2 = 1.8 x 10^-5

Write the reverse of third equation

H+ + OH- = H2O K3 = 1 x 10^14

Add the two reactions

NH3 + H+ = NH4+

Keq = K2 x K3 = 1.8 x 10^-5 x 1 x 10^14

Keq = 1.8 x 10^9

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