NB 10 Tech 10 RS 80 TOTAL 100 Data (Sodium Bicarbonate - NaHCO3): Mass (g) bq+53

Question

NB 10 Tech 10 RS 80 TOTAL 100 Data (Sodium Bicarbonate - NaHCO3): Mass (g) bq+53/Asha 61.45 Molar Mass Moles Evaporating Dish + Watch Glass Evaporating Dish + Watch Glass + NaHCO3 NaHCO3 NaCI Analysis 1. According to the balanced chemical equation, what would you expect the molar ratio of NaHCO3 to NaCl to be? Do your results agree with this? Explain. 2. What was your percent yield of NaCI? (Hint: First calculate the theoretical yield of NacI from the mole ratio of reactant to product. HCI is added in excess). 3. List at least two possible sources of error that may have caused your yield to be lower than 100%

Explanation / Answer

Ans 1

Part 1

The balanced reaction

HCl(aq) + NaHCO3(s) = NaCl(aq) + H2O(l) + CO2(g)

Stoichiometry Molar ratio of NaHCO3 to NaCl = 1 : 1

Part b

Theoretical yield of NaCl = 58.44 x 0.3/84

= 0.208 g

% yield = 0.15 x 100/0.208 = 71.868%

Part 3

Possible errors

You may be used the more reactant.

You may have the less product

Weighing balance problem

Simple arithmetic error

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