C | eztc.mheducation.com..hm.tpx KQuestion 9 (of 10) save & Exit | | Submit valu

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C | eztc.mheducation.com..hm.tpx KQuestion 9 (of 10) save & Exit | | Submit value 10.00 points 1 out of 5 attempts Use Tables A-4 and A-7. Round all percent errors to two decimal places. Assistance Check My Work View Hint View Question Guided Solution Practice This Question Print Question Help Report a Problem Determine the specific volume, internal energy, and enthalpy of compressed liquid water at 100°C and 30 MPa using the saturated liquid approximation. Compare these values to the ones obtained from the compressed liquid tables. C.L.A S.L.A. % error Specific volume Internal energy Enthalpy m'/kg kJ/kg kJ/kg m/kg kJ/kg kJ/kg 0 0, dnegg study Gad.. @ihermo ,nw ch 3-... M. Uocument1 _ word

Explanation / Answer

For Compressed liquid approximation (CLA)

Specific volume = 0.001028 m3/kg

Internal energy = 410.80 kJ/kg

Enthalpy = 441.67 kJ/kg

For Saturated liquid approximation (SLA)

Specific volume = 0.001044 m3/kg

Internal energy = 418.94 kJ/kg

Enthalpy = 419.04 kJ/kg

% error in Specific volume = (SLA-CLA)*100/SLA

= ( 0.001044 -0.001028)*100/0.001044

= 1.53%

% error in Internal energy

= ( 418.94 - 410.80)*100/418.94

= 1.94%

% error in enthalpy

= ( 419.04 - 441.67)*100/419.04

= 5.40%

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