Mystery Number: The body temperature of a whale is around 38 degrees Celsius, or
ID: 702224 • Letter: M
Question
Mystery Number: The body temperature of a whale is around 38 degrees Celsius, or 100 degrees Fahrenheit Thickness of whale blubber is 5cm (~2") thick in dolphins and smaller whales, to more than 30cm(12") in some bigger whales. Thermal conductivity of whale blubber is (0.15-0.20 W/(m C) depending on species. Ocean surface water Average temperature is about 17 degrees Celsius (62.6 degrees Fahrenheit). Deep ocean water has a very uniform temperature, around 0-3 °C Whales typically swim at-13.5m/s (14 MPH) but can go double that if in danger. Whale: http://4esoblogian blogspot.com/2012/11/seleccion-inteligente html Heat transfer coefficients 'h" for convection are typically Free Convection-Air: 5-25 (Wm2K) Free Convection -Water: 20-100 (W/m2K) Forced Convection - Air: 10-200 (WIm2K) Forced Convection -Water: 50-10.000 (W/m2K) Boiling Water: 3.000 -100.000 (W/m2K) Condensing Water Vapor: 5.000-100.000 (Wm?K) Q6: Conduction and convection: So let's say there is a whale -1.00m radius and 8.00m long (model its surface area as a cylinder) with an internal body temperature (innards excluding blubber) of 38C swimming in deep ocean water of 2.00C at a speed of 13.5m/s the entire day. The whale blubber is 0.100m thick and the forced convection heat transfer coefficient of the water is h-300. W/(m2K). There are 4187 J/Cal. A typical human diet uses-2000Cal/Day How many food Calories (Cal) does the whale need to eat each day just to stay warm?Explanation / Answer
Heat loss to surrounding by convection = h*A*(Twhale-Toutside)
A=2*3.14*r*l=2*3.14*1*8=50.24 m2
h=300 W/m2K
Twhale = 38 C
Toutside = 2 C
=> Heat loss to surrounding by convection =300*50.24*(38-2)=542592 W=542592/4187*3600*24=11196548 cal/day
Calories whale need to eat = 11196548 cal/day
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