The reaction that you performed to produce biodiesel is shown below. The R group

Question

The reaction that you performed to produce biodiesel is shown below. The R groups in the triglyceride and the biodiesel are long-chain hydrocarbon groups, with typical formula -CnHss (or something similar.) Use this equation to answer the questions below. OH NaOH (catalyst3 HcO ?? Alcohol BiodieselGlycerol (oil) You added S mL of 0.40 M NaOH in methanol to 20 mL of cooking oil. Calculate the number of moles of cooking oil, alcohol (CH OH), and base (NaOH) that are initially present in the sample before reaction takes place. In doing your calculations, assume that the 5 ml of NaOH solution contains 5 ml of methanol, with density 0.792 g/mL and molar mass 32.04 g/mol. Assume that the density of the cooking oil is 0.895 gmL and the molar mass of the oil is 885.4 g/mol. 1. Before reaction- #oa moles of triglyceride 0. 02022 mo) 0. 123lomol 0.002 mol 20mLxO.S15:nA | -or moles of methanol #ofroles of NaOH 3.90/32 .0 Assume that your biodiesel synthesis reacts to 100% completion. how many moles of each reaction component will be present? NOTE: Consider the fact that the reaction has a limiting reagent and remember that 3 moles of 2. After reaction is complete, methanol react with each mole of triglyceride After reaction- # of moles of # of moles of | # of moles of NaOH # of moles of biodiesel # of moles of glycerol seeride methanol

Explanation / Answer

The calculations before the reaction are correct, for after the reaction:

We determine the reactive limit, testing with Trigliceride:

0.02022 mol Tri * (3 mol Alcohol / 1 mol Tri) = 0.06066 mol Alcohol required

since the moles of alcohol available are more than the moles of alcohol needed for the triglyceride to disappear, then the triglyceride is the limit reagent, and the following calculations will be based on it.

Mol Triglyceride: 0 moles. is the reactive limit in a 100% conversion reaction.

mol NaOH = 0.002 mol. It is a catalyst, and it does not react in any way.

Mol Alcohol: 0.1236 - 0.06066 = 0.06294 mol alcohol remaining.

mol Biodiesel: 0.02022 mol Tri * (3 mol Biodiesel / 1 mol Tri) = 0.06066 mol Biodiesel.

mol Glycerol: 0.02022 mol Tri * (1 mol Glycerol / 1 mol Tri) = 0.06066 mol Glycerol.

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