or the electrolysis of aqueous CuCl2 using platinum (inert) electrodes. Find: Th
ID: 704445 • Letter: O
Question
or the electrolysis of aqueous CuCl2 using platinum (inert) electrodes. Find: The half-reaction at the Cathode: The half-reaction at the Anode: The overall redox reaction: Product(s) at the Anode Product(s) at the Cathode: The minimum voltage required For the electrolysis of Na SO) using carbon (inert) electrodes. Find The half-reaction at the Cathode: The half-reaction at the Anode: The overall redox reaction: Product(s) at the Cathode Product(s) at the Anode The minimum voltage required For the electrolysis of Cusoson) using inert electrodes. Find: The half-reaction at the Cathode The half-reaction at the Anode: The overall redox reaction: Product(s) at the Cathode: The minimum voltage required Product(s) at the AnodeExplanation / Answer
1)
half reaction at cathode
Cu2+(aq) + 2e - - - - > Cu(s) E° = +0.34V
half reaction at anode
2Cl-(aq) - - - - - - > Cl2(g) + 2e E° = - 1.36V
The overall redox reaction
Cu2+(aq) + 2Cl- (aq) - - - - - - > Cu(s) + Cl2(g)
E°= +0.34V + (-1.36V) = - 1.02V
products at cathode : Cu
products at anode : Cl2
The minimum voltage required : 1.02V
2)
half reaction at cathode
4H2O(l) + 4e - - - - > 2H2(g) + 4OH-(aq) E°= - 0.83V
half reaction at anode
2H2O(l) - - - - - - > 4H+(aq) + O2(g) + 4e E° = - 1.23V
overall reaction
6H2O(l) - - - > 2H2(g) + O2(g) + 4H+(aq) + 2OH-(aq)
E° = - 0.83V + (-1.23V) = - 2.06V
product at cathode : H2
product at anode : O2
minimum Voltage required : 2.06V
3)
Half reaction at cathode
2Cu2+(aq) + 4e - - - - - - > 2Cu(s) E° = +0.34V
Half reaction at anode
2H2O(l) - - - - - > 4H+(aq) + O2(g) + 4e E° = - 1.23V
overall reaction
2Cu2+(aq) + 2H2O(l) - - - - - > 2Cu(s) + 4H+(aq) + O2(g)
E° = +0.34 + (-1.23) = - 0.89V
products at cathode : Cu
products at anode : O2
minimum voltage required : 0.89V
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