Problem 1 For each molecule or ion, determine the if each intermolecular forces

Question

Problem 1 For each molecule or ion, determine the if each intermolecular forces are present (LDF, dipole-dipole, and/or hydrogen bonding). SF4: LDF present? Dipole-dipole present? Hydrogen bonding present? Submit Answer Tries o/5 KrCl2: LDF present? Dipole-dipole present? Hydrogen bonding present?Y Submit Answer Tries 0/5 PCls: LDF present? Dipole-dipole present? Hydrogen bonding present? Submit Answer Tries 0/5 XeCl2: LDF present? Dipole-dipole present? Hydrogen bonding present? Submit Answer Tries o/5 SeF2: LDF present? Dipole-dipole present? | ? | Hydrogen bonding present?Y Submit Answer Tries 0/5

Explanation / Answer

SF4 has a net dipole in the molecule because of its see saw structure, so the dipole-dipole interactions can be found here, Hbonding cannot be found here since no hydrogens are present in this molecule. Lodon dispersive forces will play a limited role here. This so because LDF is generated as a result of the loss of symmetry in the electron distribution there by causing an instantaneous polarisation leading to attraction between the two molecules. or there is a transient dipole moment generation for the LDF to come into the picture.

KrCl2 The structure is linear, so there is no net dipole moment in the molecule. There are chances of formation of instantaneous dipoles leading to attraction between different molecules. Thus LDF will be present in this case. the diole-dipole interactions and Hydrogen bonding interactions will be absent since no hydrogens are attached.

PCl5 The structure of this molecule is trigonal bipyramidal and it has no permanent dipole moment in the molecule. So dipole-dipole interactions and hydrogen bonding interactions is out of the picture. LDF is a possibility since each P-Cl bond in PCl5 is polarised there are chances of instantaneous dipoel formation formation leading to the formation of London forces. Hydrogen bonding will be absent since no hydrogens are present in the molecule.

XeCl2 structure is linear. So, LDF is possible. This case similar to KrCl2.

SeF2 has a bent structure like water molecule. So, the molecule will have a permanent dipole moment and so dipole-dipole interactions will be important here. Hydrogen bonding and LDF will be absent.

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