Chem Activity: Waves, Spectroscopy, and Quantum Numbers The following problems a

Question

Chem Activity: Waves, Spectroscopy, and Quantum Numbers The following problems are related to waves, spectroscops, and quentum mumbers You are to work on these problens in snall groups during the allotted class time Be sure to show all your work Aw rwbls ssver de tlete lw the end of class sure to show all your work. Any peoblems you do not will become homework that is due at the begiuning of the next leeture 1. While sitting on a dock along Laloe Michigan, you notice waves in the witer moving towards the shore. You decide to count the number of waves that pass by you on the dock. In 5.00 min and 20.0 sec, a total of 100 wave crests pass by. You also ote that it takes the waves 10.0 sec to travel from where you are on the dock to the shore which is a distance of 20.0 ft. hi a. What is the frequency of the waves? ah b. What is the speed (in ft/s) of the waves? is the wavelength (in ft) of the waves? Li 2. Complete the following table Orbital(s)Electrons he 42 io

Explanation / Answer

1. Frequency is the number of waves that pass in one second.

Given that, 100 waves pass by within time 5 min 20 sec.

5 min 20 sec = [(60 sec x 5) + 20] = 320 sec

In 320 sec, 100 waves pass by.

Hence in 1sec, number of waves that pass = 100/320 = 0.31 s-1.

2. Given, distance = 20 ft

Time = 10 sec

Speed of the waves = Distance / Time

= 20 / 10

= 2 ft / s

3. Wavelength = Velocity of wave / Frequency

= 2 fts-1/ 0.31s-1

= 6.45 ft

4. The quantum numbers ranges are:

Principal quantum number (n) = 1 to n

Azimuthal quantum number (l) = 0 to n-1

Magnetic quantum number (m) = -l to +l

Spin quantum number (s) = +1/2 and -1/2

When n=3, l = 0,1,2, m = -2,-1,0,1,2, Name of orbitals = 3s, 3p, 3d, Number of electrons = 2n2 = 2 x (3)2 = 18 electrons

When l = 3, n = 4, m = -3,-2,-1,0,1,2,3, Name of orbital = 4f, Number of electrons = 14 electrons. (Since maximum 2 electrons can be accomodated in a given orbital. 7 orbitals will occupy 14 electrons)

When m = 2, l = 2, n = 3, Name of orbital = 3d, Number of electrons = 2 electrons (Since maximum 2 electrons can be accomodated in a given orbital)

When l = 0, n = 1, m = 0, Name of orbital = 1s, Number of electrons = 2 electrons. (Since maximum 2 electrons can be accomodated in a given orbital.)

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