1, write the 5.4% glucose as a conversion factor. 2. Write the concentration 2.5
ID: 706824 • Letter: 1
Question
1, write the 5.4% glucose as a conversion factor. 2. Write the concentration 2.5M NacI as a conversion factor We dissolve 6.88 g of KOH in 200.0 g water. What is the mass percent of KOH in the solution? 4. How many moles of sugar are contained in 550. mL of 5.00 M sugar solution? 5. If 25.0 mL of 2.0 M NaCI is diluted to a total volume of 300.0 mL, what is its new molarity? 6. How many liters of hydrogen gas at STP would be prepared from 250.0 mL of 0.40M HNO, solution? 2Al(s) +6HNOs(aq) 2AI(NO3)3(aq)+ 3H2(g)Explanation / Answer
1)
the conversion factor is fraction that indicates the relationship between two units.
So, 5. 4% glucose = 5.4 unit of glucose / 100 unit of solution
2)
Similarly, 2.5 M NaCl = 2.5 mol of NaCl / 1 L of solution
3)
mass% of KOH in solution
= ( mass of KOH / mass of solution) x 100
= (6.88 / 200) x 100
= 3.44 %
4)
Moles of sugar = volume of solution in litres x molarity
= 0.550 L x 5 mol / L
= 2.75 mol
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