While ethanol (CHCH2OH is produced naturally by fermentation, e.g. in beer- and
ID: 707301 • Letter: W
Question
While ethanol (CHCH2OH is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting ethylene CH2CH2) with water vapor at elevated temperatures. A chemical engineer studying this reaction fills a 500. mL flask at 20. °C with 0.70 atm of ethylene gas and 4.5 atm of water vapor. He then raises the temperature considerably, and when the mixture has come to equilibrium determines that it contains 0.38 atm of ethylene gas and 4.18 atm of water vapor. The engineer then adds another 0.23 atm of ethylene, and allows the mixture to come to equilibrium again. Calculate the pressure of ethanol after equilibrium is reached the second time. Round your answer to 2 significant digits. atm x10Explanation / Answer
Balanced chemical reaction with ICE TABLE
C2H4(g) + H2O(g) <===> CH3CH2OH(g)
I 0.70 4.5
C - x - x +x
E 0.70-x 4.5-x x
After equilibrium
P(C2H4) = 0.38 atm
0.70 - x = 0.38
x = 0.32 atm
P(H2O) = 4.18 atm
4.5 - x = 4.18
x = 0.32 atm
P(CH3CH2OH) = 0.32 atm
Equilibrium constant expression of the reaction
Kp = 0.32 / (4.18)*(0.38)
= 0.2015
Now add 0.23 arm of C2H4
New pressure = 0.23+0.70 = 0.93 atm
Balanced chemical reaction with ICE TABLE
C2H4(g) + H2O(g) <===> CH3CH2OH(g)
I 0.93 4.5
C - x - x +x
E 0.93-x 4.5-x x
Equilibrium constant expression of the reaction
Kp = x / (4.5-x)*(0.93-x)
0.2015 * (4.5-x)*(0.93-x) = x
(0.90675 - 0.2015 x) * (0.93-x) = x
0.8432775 - 0.90675 x - 0.187395 x + 0.2015 x2 - x = 0
0.2015 x2 - 2.094145 x + 0.8432775 = 0
x = 0.4196
After second equilibrium
P(CH3CH2OH) = 0.4196 = 4.196*10^-1 atm
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